\(\left|x-2\right|=\left|3-2x\right|\Leftrightarrow\left[{}\begin{matrix}x-2=3-2x\\x-2=2x-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-1\end{matrix}\right.\)
Vậy tích các gt của x là \(-\dfrac{5}{3}\)
\(\left|x-1\right|=\dfrac{4}{5}\Leftrightarrow\left[{}\begin{matrix}x-1=\dfrac{4}{5}\\1-x=\dfrac{4}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{5}\\x=\dfrac{1}{5}\end{matrix}\right.\\ \Leftrightarrow\sum x=\dfrac{9}{5}+\dfrac{1}{5}=2\)
\(\left|x-1\right|=\dfrac{4}{5}\)
\(x=\dfrac{9}{5}\) hoặc \(\dfrac{1}{5}\)
\(=>\dfrac{9}{5}+\dfrac{1}{5}=\dfrac{10}{5}=2\)
