1: ΔABC đều
=>AB=AC=BC=a và \(\hat{BAC}=\hat{ABC}=\hat{ACB}=60^0\)
\(\overrightarrow{AB}\cdot\overrightarrow{AC}\)
\(=AB\cdot AC\cdot cosBAC\)
\(=a\cdot a\cdot cos60=\frac{a^2}{2}\)
2: \(\overrightarrow{AN}=\overrightarrow{AB}+\overrightarrow{BN}\)
\(=\overrightarrow{AB}+\frac13\cdot\overrightarrow{BC}=\overrightarrow{AB}+\frac13\left(\overrightarrow{BA}+\overrightarrow{AC}\right)\)
\(=\overrightarrow{AB}-\frac13\cdot\overrightarrow{AB}+\frac13\cdot\overrightarrow{AC}=\frac23\cdot\overrightarrow{AB}+\frac13\cdot\overrightarrow{AC}\)

