Bài 1:
a) ĐKXĐ: \(x\notin\left\{0;-3\right\}\)
b) Ta có: \(A=\dfrac{1-x^2}{x}\cdot\left(\dfrac{x^2}{x+3}-1\right)+\dfrac{3x^2-14x+3}{x^2+3x}\)
\(=\dfrac{\left(1-x\right)\left(1+x\right)}{x}\cdot\dfrac{x^2-x-3}{x+3}+\dfrac{3x^2-14x+3}{x\left(x+3\right)}\)
\(=\dfrac{\left(1-x^2\right)\left(x^2-x-3\right)+3x^2-14x+3}{x\left(x+3\right)}\)
\(=\dfrac{x^2-x-3-x^4+x^3+3x^2+3x^2-14x+3}{x\left(x+3\right)}\)
\(=\dfrac{-x^4+x^3+7x^2-15x+3}{x\left(x+3\right)}\)
Đúng 1
Bình luận (0)
