\(b,\Rightarrow\left|\dfrac{5}{4}-2x\right|=\dfrac{1}{6}\\ \Rightarrow\left[{}\begin{matrix}\dfrac{5}{4}-2x=\dfrac{1}{6}\\2x-\dfrac{5}{4}=\dfrac{1}{6}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=\dfrac{13}{12}\\2x=\dfrac{17}{12}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{13}{24}\\x=\dfrac{17}{24}\end{matrix}\right.\)
\(0,5-\left|\dfrac{5}{4}-2x\right|=\dfrac{1}{3}\)
<=> \(\left[{}\begin{matrix}0,5-\left(\dfrac{5}{4}-2x\right)=\dfrac{1}{3}\left(x\ge\dfrac{5}{8}\right)\\0,5-\left[-\left(\dfrac{5}{4}-2x\right)\right]=\dfrac{1}{3}\left(x< \dfrac{5}{8}\right)\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=\dfrac{13}{24}\left(loại\right)\\x=\dfrac{17}{24}\left(loại\right)\end{matrix}\right.\)
Vậy nghiệm của PT là \(S=\varnothing\)
