\(\left(x-\dfrac{1}{2}\right)^2=0\) ⇔\(x=\dfrac{1}{2}\)
\(\left(x-2\right)^2=1\text{⇔}\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)
\(\left(2x-1\right)^3=-8\text{⇔}x=\dfrac{1}{2}\)
\(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\text{⇔}\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=\dfrac{3}{4}\end{matrix}\right.\)
1) \(\left(x-\dfrac{1}{2}\right)^2=0\Rightarrow x=\dfrac{1}{2}\)
2) \(\left(x-2\right)^2=1\)
\(\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)
3) \(\left(2x-1\right)^3=-8\)
\(\Rightarrow2x-1=-2\Rightarrow x=-\dfrac{1}{2}\)
4) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{4}\\x+\dfrac{1}{2}=-\dfrac{1}{4}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=-\dfrac{3}{4}\end{matrix}\right.\)
