\(a,BC=\sqrt{AB^2+AC^2}=\sqrt{16+48}=\sqrt{64}=8\left(cm\right)\)
Áp dụng HTL tam giác
\(\left\{{}\begin{matrix}AB^2=BH\cdot BC\\AC^2=CH\cdot BC\\AH^2=CH\cdot BH\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}BH=\dfrac{AB^2}{BC}=2\left(cm\right)\\CH=\dfrac{AC^2}{BC}=6\left(cm\right)\\AH=\sqrt{2\cdot6}=2\sqrt{3}\left(cm\right)\end{matrix}\right.\)

