a: Ta có: \(\frac{x-4}{6}+\frac12>\frac{2x-5}{3}\)
=>\(\frac{x-4+3}{6}>\frac{2\left(2x-5\right)}{6}\)
=>2(2x-5)<x-1
=>4x-10<x-1
=>3x<9
=>x<3
b: \(\frac{x+6}{5}-\frac{x-2}{3}<2\)
=>\(\frac{3\left(x+6\right)-5\left(x-2\right)}{15}<2\)
=>3(x+6)-5(x-2)<30
=>3x+18-5x+10<30
=>-2x+28<30
=>-2x<2
=>x>-1
