a) \(4x^4-4x^2+1=\left(2x^2-1\right)^2\) b) \(\left(x+2y\right)^2=x^2+4xy+4y^2\)
a) \(36+x^2-12x=\left(x-6\right)^2\) b)\(\left(x+5y\right)^2=x^2+10xy+25y^2\)
a) \(4x^2-12x+9=\left(2x-3\right)^2\) b) \(\left(x-2y\right)^2=x^2-4xy+4y^2\)
a) \(1-10x+25x^2=\left(1-5x\right)^2\) b) \(\left(3x+5y\right)^2=9x^2+30xy+25y^2\)
4x4 - 4x2 +1 = (2x2)2 - 2.2x2.1 + 12= (2x2 -1 )2
36 + x2 -12x = 36 -12x +x2 = 62 -2.6.x +x2 = (6-x)2
4x2 - 12x +9 = (2x)2 - 2.2x.3 + 32 = (2x - 3)2
1 -10x +25x2 = 12 - 2.1.5x + (5x)2 = (1 - 5x)2
x4 +81 + 18x2 = x4 +18x2 +81= (x2)2 + 2.x2.9 + 92= (x2+9)2
x2+ 4y4 - 4xy2= x2- 4xy2 +4y4= x2- 2.x.2y2 + (2y2)2= (x-2y2)2
x2+ 10xy +25y2= x2 + 2.x.5y + (5y)2= (x+5y)2
9y2 - 24xy +16x2= (3y)2 - 2.3y.4x +(4x)2 = (3y -4x)2
16x2 + 9y4 +24xy2 = 16x2 +24xy2 + 9y4= (4x)2+2.4x.3y2+ (3y2)2= (4x+3y2)2
Học tốt!
a) \(x^4+81+18x^2=\left(x^2+9\right)^2\) b)\(\left(3y-4x\right)^2=9y^2-24xy+16x^2\)
a) \(x^2+4y^4-4xy^2=\left(x-2y^2\right)^2\) b)\(\left(2x-3y\right)^2=4x^2-12xy+9y^2\)
a) \(x^2+10xy+25y^2=\left(x+5y\right)^2\) b) \(\left(2x-5y\right)^2=4x^2-20xy+25y^2\)
a) \(9y^2-24xy+16x^2=\left(3y-4x\right)^2\) b) \(\left(2x+3y\right)^2=4x^2+12xy+9y^2\)
a) \(16x^2+9y^4+24xy^2=\left(4x+3y^2\right)^2\) b) \(\left(3x-5y\right)^2=9x^2-30xy+25y^2\)
\(4x^4-4x^2+1=\left(2x^2-1\right)^2\)
\(36-12x+x^2=\left(6-x\right)^2\)
\(4x^2-12x+9=\left(2x-3\right)^2\)
\(25x^2-10x+1=\left(5x-1\right)^2\)
\(x^4+18x^2+81=\left(x^2+9\right)^2\)
\(x^2-4xy^2+4y^4=\left(x-2y^2\right)^2\)
\(x^2+10xy+25y^2=\left(x+5y\right)^2\)
\(9y^2-24xy+16x^2=\left(3y-4x\right)^2\)
\(16x^2+24xy^2+9y^4=\left(4x+3y^2\right)^2\)
\(\left(x+2y\right)^2=x^2+4xy+4y^2\)
\(\left(x+5y\right)^2=x^2+10xy+25y^2\)
\(\left(x-2y\right)^2=x^2-4xy+4y^2\)
\(\left(3x+5y\right)^2=9x^2+30xy+25y^2\)
\(\left(3y-4x\right)^2=9y^2-24xy+16x^2\)
\(\left(2x-3y\right)^2=4x^2-12xy+9y^2\)
