Question

Answer 1

6: ĐKXĐ: -2<=x<=22/3

\(4\sqrt{x+2}+\sqrt{22-3x}-x^2-8=0\)

=>\(4\sqrt{x+2}-8-x^2+4+\sqrt{22-3x}-4=0\)

=>\(4\left(\sqrt{x+2}-2\right)-\left(x-2\right)\left(x+2\right)+\frac{22-3x-16}{\sqrt{22-3x}+4}=0\)

=>\(4\cdot\frac{x-2}{\sqrt{x+2}+2}-\left(x-2\right)\left(x+2\right)+\frac{-3x+6}{\sqrt{22-3x}+4}=0\)

=>\(\left(x-2\right)\left(\frac{4}{\sqrt{x+2}+2}-x-2-\frac{3}{\sqrt{22-3x}+4}\right)=0\)

=>x-2=0

=>x=2(nhận)