Question

Answer 1

Dạng 2:

a. $-0,8\sqrt{(-0,125)^2}=-0,8|-0,125|=-0,8.0,125=-0,1$

$\sqrt{(-2)^6}=|(-2)^3|=8$

$\sqrt{(\sqrt{3}-2)^2}=|\sqrt{3}-2|=2-\sqrt{3}$

b.

$\sqrt{(\frac{1}{\sqrt{2}}-\frac{1}{\sqrt{3}})^2}=|\frac{1}{\sqrt{2}}-\frac{1}{\sqrt{3}}|=\frac{1}{\sqrt{2}}-\frac{1}{\sqrt{3}}$

$\sqrt{(0,1-\sqrt{0,1})^2}=|0,1-\sqrt{0,1}|=\sqrt{0,1}-0,1$

$\sqrt{4-2\sqrt{3}}=\sqrt{(\sqrt{3}-1)^2}=|\sqrt{3}-1|=\sqrt{3}-1$

c.

$\sqrt{3+2\sqrt{2}}=\sqrt{(\sqrt{2}+1)^2}=\sqrt{2}+1$

$\sqrt{9-4\sqrt{5}}=\sqrt{(2-\sqrt{5})^2}=|2-\sqrt{5}|=\sqrt{5}-2$
$\sqrt{16-6\sqrt{7}}=\sqrt{(3-\sqrt{7})^2}=3-\sqrt{7}$