a, Ta có : \(\left\{{}\begin{matrix}\left(\sqrt{26}+3\right)^2=35+6\sqrt{26}=35+\sqrt{936}\\\left(\sqrt{63}\right)^2=63=35+\sqrt{784}\end{matrix}\right.\)
Thấy : \(936>784\)
\(\Rightarrow\sqrt{26}+3>\sqrt{63}\)
b, Ta có : \(3< 4\)
\(\Rightarrow\dfrac{\sqrt{3}}{2}< \dfrac{\sqrt{4}}{2}=1\)
\(\Rightarrow\dfrac{\sqrt{3}-1}{2}< 1-\dfrac{1}{2}=\dfrac{1}{2}\)
Vậy ...
a) Ta có: \(\left(\sqrt{26}+3\right)^2=35+6\sqrt{26}\)
\(\left(\sqrt{63}\right)^2=63=35+28\)
mà \(6\sqrt{26}=\sqrt{936}>\sqrt{784}=28\)
nên \(\sqrt{26}+3>\sqrt{63}\)
b) Ta có: \(1-\sqrt{3}+1=2-\sqrt{3}>0\)
nên \(1>\sqrt{3}-1\)
\(\Leftrightarrow\dfrac{1}{2}>\dfrac{\sqrt{3}-1}{2}\)
