\(\left|2x+3\right|-x=3\)   (1)

TH1: \(2x+3\ge0\Rightarrow x\ge-\dfrac{3}{2}\)

\(\left(1\right)\Rightarrow2x+3-x=3\Rightarrow x=0\) (TM)

TH2: \(2x+3< 0\Rightarrow x< -\dfrac{3}{2}\)

(1) \(\Rightarrow-2x-3-x=3\Rightarrow-3x=6\Rightarrow x=-2\) (TM)

Vậy \(x=0;x=-2\)

a) \(3^2.5+\left(\dfrac{10}{5}\right)^3.10-81:3\)

\(=9.5+8.10-81:3\\ =45+80-27\\ =98\)

b) \(-4^3.71+32.29-13.\left(-\dfrac{1}{50\%}\right)^5\)

\(=-64.71+32.29-13.\left(-2\right)^5\\ =-32.142+32.29+32.13\\ =32.\left(-142+29+13\right)\\ =32.\left(-100\right)\\ =-3200\)