tan \(B=\frac{AC}{AB}=\frac{5}{12}\)

\(\Rightarrow\frac{AC}{6}=\frac{5}{12}=>AC=\frac{5}{2}cm\)

TA CÓ \(AB^2+AC^2=BC^2\)

\(\Rightarrow6^2+(\frac{5}{2})^2=BC^2\)

\(\Rightarrow BC^2=\frac{169}{4}\Rightarrow BC=\frac{13}{2}cm\)

ta có AB.AC=AH.BC=>6.5/2=AH.13/2=> AH=80/13

\(AM=\frac{1}{2}.AC=\frac{5}{4}cm\)

\(BM^2=AB^2+AM^2=6^2+\left(\frac{5}{4}\right)^2=\frac{601}{16}\)

\(\Rightarrow BM=\frac{\sqrt{601}}{4}\)

I,

1 higher

2 economically

3 valueless

4 inadvisable

5 comparatively

6 industrious

7 popularity

8 electrified

9 unemployable

10 calculating

II

1 hundred ->a/one hundred

2 percents-> percent

3 the highest-> higher

4 are -> is

5 financial-> finance

III

1 c

2a

3a

4d

5c

6a

7c

8d

9c

10c

11b

12d

13d

14a

15b

16

c

17d

18b

19b

20b

ĐPCM là gì

\(=\left(2+\sqrt{3}+\sqrt{2}-1\right)\left(1+\sqrt{2}-\sqrt{3}\right)\)

\(=\left(1+\sqrt{3}+\sqrt{2}\right)\left(1+\sqrt{2}-\sqrt{3}\right)=2\sqrt{2}\)