giải phương trình

1, \(-2x^3+10x^2-17x+8=2x^2\sqrt[3]{5x-x^3}\)

2,\(3\left(x^2+2x+2\right)=10\sqrt{x^3+2x^2+2x+1}\)

3, \(x^3-3x^2+2=\sqrt{x+1}\)

4,\(\sqrt{x^4+x^2+1}+\sqrt{3}\left(x^2+1\right)=3\sqrt{3}x\)

\(gpt:\left(2x^2-x-3\right)\sqrt{x^2+x+2}+\left(2x^2+x+1\right)\sqrt{x+3}=0\)

Giải hpt

\(\left\{{}\begin{matrix}\sqrt{x^2+2x+22}-\sqrt{y}=y^2+2y+1\\\sqrt{y^2+2y+22}-\sqrt{x}=x^2+2x+1\end{matrix}\right.\)

\(\left\{{}\begin{matrix}xy-x-y=1\\4x^3-12x^3+9x=-y^3+6y+7\end{matrix}\right.\)

tìm giá trị của m để hpt sau có nghiệm duy nhất

\(\left\{{}\begin{matrix}3x-m\sqrt{y^2+1}=1\\x+y+\dfrac{1}{y+\sqrt{y^2+1}}=m^2\end{matrix}\right.\)

giải hpt

\(\left\{{}\begin{matrix}\dfrac{1}{\sqrt{x}}+\dfrac{y}{x}=2\dfrac{\sqrt{x}}{y}+2\\y\left(\sqrt{x^2+1}-1\right)=\sqrt{3x^2+3}\end{matrix}\right.\)

\(\left\{{}\begin{matrix}x^3-3x^2+5x+1=4y\\y^3-3y^2+5y+1=4z\\z^3-3z^2+5z+1=4x\end{matrix}\right.\)

giải hpt

\(\left\{{}\begin{matrix}\sqrt{x^2+2x+22}-\sqrt{y}=y^2+2y+1\\\sqrt{y^2+2y+22}-\sqrt{x}=x^2+2x+1\end{matrix}\right.\)

\(\left\{{}\begin{matrix}xy-x-y=1\\4x^3-12x^2+9x=-y^3+6y+7\end{matrix}\right.\)

giải hệ phương trình

\(\left\{{}\begin{matrix}\left(2x-y+2\right)\left(2x+y\right)+6x-3y+6=0\\\sqrt{2x+1}+\sqrt{y-1}=4\end{matrix}\right.\)

\(\left\{{}\begin{matrix}\sqrt{x}-\sqrt{x-y-1}=1\\y^2+x+2y\sqrt{x}-y^2x=0\end{matrix}\right.\)

GPT

\(x^3+3x^2+4x+2=\left(3x+2\right)\sqrt{3x+1}\)

\(x^4+2x^3+2x^2-2x+1=\left(x^3+x\right)\sqrt{\dfrac{1-x^2}{x}}\)

\(x^{4n}+\sqrt{x^{2n}+2022}=2022\)

gpt: \(2\sqrt[2023]{\left(1+x\right)^2}+3\sqrt[2023]{1-x^2}+\sqrt[2023]{\left(1-x\right)^2}=0\)