HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
\(x^2-10x=-25\)
\(\Leftrightarrow x^2-10x+25=0\)
\(\Leftrightarrow\left(x-5\right)^2=0\Leftrightarrow x-5=0\Leftrightarrow x=5\)
Rut gon:
\(D=\dfrac{y}{3-y}+\dfrac{y^2+3y}{2y+3}\left(\dfrac{y+3}{y^2-3y}-\dfrac{y}{y^2-9}\right)\)
\(B=\left(\dfrac{x}{x-1}-\dfrac{x+1}{x}\right):\left(\dfrac{x}{x+1}-\dfrac{x-1}{x}\right)\)
\(x^2-10x+16=0\)
\(\Leftrightarrow x^2-8x-2x+16=0\)
\(\Leftrightarrow x\left(x-8\right)-2\left(x-8\right)=0\)
\(\Leftrightarrow\left(x-8\right)\left(x-2\right)=0\) \(\Leftrightarrow\) \(\left[{}\begin{matrix}x-8=0\\x-2=0\end{matrix}\right.\) \(\Leftrightarrow\) \(\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Rut gon :
\(A=\dfrac{x^2-1}{x+10}\cdot\dfrac{2x}{x+2}+\dfrac{x^2-1}{x+10}\cdot\dfrac{10-x}{x+2}\)
rut gon bieu thuc :
\(A=\left(\dfrac{6x+1}{x^2-6x}+\dfrac{6x-1}{x^2+6x}\right).\dfrac{x^2-36}{x^2+1}\)