Ta có:\(f\left(x\right)⋮4x-1\Rightarrow f\left(\dfrac{1}{4}\right)=0\)
\(f\left(x\right)⋮x+3\Rightarrow f\left(-3\right)=0\)
Ta có hpt:\(\left\{{}\begin{matrix}2\left(\dfrac{1}{4}\right)^2a+\dfrac{1}{4}b-3=0\\2.\left(-3\right)^2a-3b-3=0\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}a=2\\b=11\end{matrix}\right.\)