Ta có: (x+5)(2x-1)=(2x-3)(x+1)
\(\Leftrightarrow2x^2-x+10x-5=2x^2+2x-3x-3\)
\(\Leftrightarrow2x^2+9x-5-2x^2+x+3=0\)
\(\Leftrightarrow10x-2=0\)
\(\Leftrightarrow10x=2\)
hay \(x=\frac{1}{5}\)
Vậy: \(x=\frac{1}{5}\)
Ta có: (x+5)(2x-1)=(2x-3)(x+1)
\(\Leftrightarrow2x^2-x+10x-5=2x^2+2x-3x-3\)
\(\Leftrightarrow2x^2+9x-5-2x^2+x+3=0\)
\(\Leftrightarrow10x-2=0\)
\(\Leftrightarrow10x=2\)
hay \(x=\frac{1}{5}\)
Vậy: \(x=\frac{1}{5}\)
A, x/2x+6 - x/2x+2= 3x+2/(x+1)(x+3)
B, 5/x+7+8/2x+14= 2/3
C, x-1/x-1/x+1= 2x-1/x^2+x
a. 1+2x-5/6 + 3- x/4
b. x+1/2 - x-2/3
c. 2x-1/3 +x =x+4
d. x+5/4 -2x-3/3 -6x-1/8 + 2x-1/12
Mọi người giúp em với đề này khó quá
Giải các phương trình
a)3x-2=2x-3 c)11x+42-2x=100-9x-22
b)2x+3=5x+9 d)2x-(3-5x)=4(x+3)
e)\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
f)\(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)
g)(2x+1)(x-1)=0
h)(x+\(\dfrac{2}{3}\))(x-\(\dfrac{1}{2}\))=0
i)(3x-1)(2x-3)(2x-3)(x+5)=0
k)3x-15=2x(x-5)
m)\(\left|x-2\right|=3\)
n)\(\left|x+1\right|=\left|2x+3\right|\)
j)\(\dfrac{7x-3}{x-1}=\dfrac{2}{3}\)
đ)\(\dfrac{2\left(3-7x\right)}{1+x}=\dfrac{1}{2}\)
y)\(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\)
\(\dfrac{1}{x-1}+\dfrac{2}{x+1}=\dfrac{x}{x^2-1}\)
bài 1
a \(\frac{3x}{x-2}-\frac{x}{x-5}+\frac{2x^2}{7x-10-x^2}\)=0
b\(\frac{2x+5}{x+3}-\frac{2x+2}{\left(x-1\right)\left(x+3\right)}=\frac{3x-1}{x-1}\)
c (2x-1)\(^2\)- (2x+1)\(^2\)=4(x-3)
7+2x=22-3x
x-12+4x=25+2x-1
7-(2x+4)=-(x+4)
8x-3=5x+12
x+2x+3x-19=3x+5
(x-1)-(2x-1)=9-x
1) Giải các pt sau:
a) \(\frac{x-3}{5}=6-\frac{1-2x}{3}\)
b) \(\frac{3x-2}{6}-5=\frac{3-2\left(x+7\right)}{4}\)
c) \(\frac{x+8}{6}-\frac{2x-5}{5}=\frac{x-1}{3}-x+7\)
d) \(\frac{7x}{8}-5\left(x-9\right)=\frac{2x+1,5}{6}\)
e) \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x+1\right)}{7}-5\)
f) \(\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)
giải phương trình
[x - 6] [ 2x -5 ] [ 3x + 9 ] = 0
2x [ x - 3 ] + 5 [ x - 3 ] = 0
[ 4 - x ]2 - [ x - 2 ] [ 3 - 2x ] = 0
3x [x2 + 1 ] [ x - 2 ] =0
[ 3x + 5 ] [ x2 + x + 1 ] = 0
1) x2 - x - (3x - 3) = 02) x(x - 6) - 7x + 42 = 0
3) x3 - 3x2 + 3x - 1 = 0
4) (2x - 5)2 - (x + 2) 2 = 0
5) x(2x - 9) = 3x(x - 5)
A) 1/4(x+3)=3-1/2(x+1)-1/3(x+2)
B) 3x-11/11-x/3=3x-5/7-5x-3/9
C) x-3/17(2x-1)=7/34(1-2x)+10x-3