Question

x.(3x-2)-5.(2-3x)=0

Answer 1

Answer 2

x(3x - 2) - 5(2 - 3x )=0

⇒ x( 3x -2) + 5(3x - 2)=0

⇒( x + 5 )( 3x - 2 )=0

+) x + 5 = 0 ⇒x = -5

+) 3x - 2 = 0 ⇒ 3x = 2 ⇒ x = \(\dfrac{2}{3}\)

Vậy x ϵ { -5 ; \(\dfrac{2}{3}\) }

Answer 3

\(x\left(3x-2\right)-5\left(2-3x\right)=0\)

\(\Leftrightarrow x\left(3x-2\right)+5\left(3x-2\right)=0\)

\(\Leftrightarrow\left(3x-2\right)\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-2=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x_1=\dfrac{2}{3}\\x_2=-5\end{matrix}\right.\)