\(\left[{}\begin{matrix}x+\dfrac{3}{2}=\dfrac{4}{3}\\x+\dfrac{3}{2}=\dfrac{-4}{3}\end{matrix}\right.\left[{}\begin{matrix}x=-\dfrac{1}{6}\\x=-\dfrac{17}{6}\end{matrix}\right.\)
\(\left|x+\dfrac{3}{2}\right|=\dfrac{4}{3}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{3}{2}=\dfrac{4}{3}\\x+\dfrac{3}{2}=-\dfrac{4}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{6}\\x=-\dfrac{17}{6}\end{matrix}\right.\)