Ý bạn là phân tích đa thức thành nhân tử hả.
\(x^3-y^3-z^3-3xyz\)
\(=\left(x^3-3x^2y+3xy^2-y^3\right)-z^3+3x^2y-3xy^2-3xyz\)
\(=\left(x-y\right)^3-c^3+3xy\left(x-y-z\right)\)
\(=\left(x-y-z\right)\left[\left(x-y\right)^2+\left(x-y\right)z+z^2\right]+3xy\left(x-y-z\right)\)
\(=\left(x-y-z\right)\left(x^2-2xy+y^2+xz-yz+c^2+3xy\right)\)
\(=\left(x-y-z\right)\left(x^2+y^2+xz-yz+c^2+xy\right)\)