Câu hỏi của dragon gold

Question

x3 + 2x2 - x - 2

Lê Nguyễn Ngọc Nhi · Accepted Answer

Ta có: $x^3+2x^2-x-2$

$=x^2\left(x+2\right)-\left(x+2\right)$

$=\left(x+2\right)\left(x^2-1\right)$

$=\left(x+2\right)\left(x-1\right)\left(x+1\right)$

Chúc bn học tốt!Câu trả lời: Ta có: $x^3+2x^2-x-2$

$=x^2\left(x+2\right)-\left(x+2\right)$

$=\left(x+2\right)\left(x^2-1\right)$

$=\left(x+2\right)\left(x-1\right)\left(x+1\right)$

Chúc bn học tốt!

Nguyen Thi Thu Hoa · Answer

$x^3+2x^2-x-2$

$=\left(x^3-x\right)+\left(2x^2-2\right)$

=$x\left(x^2-1\right)+2\left(x^2-1\right)$

$=\left(x+2\right)\left(x+1\right)\left(x-1\right)$Câu trả lời: $x^3+2x^2-x-2$

$=\left(x^3-x\right)+\left(2x^2-2\right)$

=$x\left(x^2-1\right)+2\left(x^2-1\right)$

$=\left(x+2\right)\left(x+1\right)\left(x-1\right)$

Nguyễn Huyền Trâm · Answer

Ta có: x3+2x2−x−2x3+2x2−x−2

=x2(x+2)−(x+2)=x2(x+2)−(x+2)

=(x+2)(x2−1)=(x+2)(x2−1)

=(x+2)(x−1)(x+1)Câu trả lời: Ta có: x3+2x2−x−2x3+2x2−x−2

=x2(x+2)−(x+2)=x2(x+2)−(x+2)

=(x+2)(x2−1)=(x+2)(x2−1)

=(x+2)(x−1)(x+1)

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