\(VT=\dfrac{2x^2+2xy+xy+y^2}{x^2\left(2x+y\right)-y^2\left(2x+y\right)}=\dfrac{2x\left(x+y\right)+y\left(x+y\right)}{\left(x^2-y^2\right)\left(2x+y\right)}\\ =\dfrac{\left(2x+y\right)\left(x+y\right)}{\left(2x+y\right)\left(x-y\right)\left(x+y\right)}=\dfrac{1}{x-y}=VP\)