ĐKXĐ: ...
\(\Leftrightarrow x^2+3x-2+x+2-\sqrt{x+6}=0\)
\(\Rightarrow x^2+3x-2+\frac{\left(x+2\right)^2-\left(x+6\right)}{x+2+\sqrt{x+6}}=0\)
\(\Leftrightarrow\left(x^2+3x-2\right)\left(1+\frac{1}{x+2+\sqrt{x+6}}=0\right)\)
\(\Rightarrow\left[{}\begin{matrix}x^2+3x-2=0\\x+2+\sqrt{x+6}=-1\left(1\right)\end{matrix}\right.\)
Xét (1): đặt \(\sqrt{x+6}=t\ge0\Rightarrow x=t^2-6\)
\(\Rightarrow t^2+t-3=0\)
Bạn tự giải nốt và loại nghiệm
b,,\(\sqrt{x^2+4x+8}+\sqrt{x^2+4x+4}=\sqrt{2\cdot\left(x^2+4x+6\right)}\)
Rút gọn các biểu thức sau:a. \(\frac{x+6\sqrt{x}+9}{x-9}\left(x\ge0;x\ne9\right)\)
b. \(\sqrt{6+2\sqrt{5}}-\sqrt{6-2\sqrt{5}}\)
c. 4x - \(4x-\sqrt{x^2-4x+4}\left(x\ge2\right)\)
a,\(\sqrt{4x^2+x+6}=4x-2+7\sqrt{x+1}\)
Giải pt:
\(\left(\sqrt{x+6}-\sqrt{x-2}\right)\left(1+\sqrt{x^2+4x-12}\right)=8\)
Giai phuong trinh
1/ \(\sqrt{x^2+4x+5}+\sqrt{x^2-6x+13}=3\)
2/ \(\sqrt{3x^2-18x+28}+\sqrt{4x^2-24x+45}=6x-x^2-5\)
3/ \(\sqrt{2x^2-4x+27}+\sqrt{3x^2-6x+12}=4x^2+8x+4\)
4/ \(\sqrt{x^2+x+7}+\sqrt{x^2+x+2}=\sqrt{3x^2+3x+19}\)
5/ \(\left(x+2\right)\left(x+3\right)-\sqrt{x^2+5x+1}=9\)
6/ \(\left(x+4\right)\left(x+1\right)-3\sqrt{x^2+5x+2}=6\)
7/ \(\sqrt{2x^2+3x+5}+\sqrt{2x^2-3x+5}=3\sqrt{x}\)
Giải phương trình : \(\sqrt{x^2+4x+9}+\sqrt{x^2-4x+9}=6\)
\(\left(\frac{x}{\sqrt{x}-2}-\frac{4x-4\sqrt{x}}{x-2\sqrt{x}}\right)\cdot\frac{6}{\left(\sqrt{x}-2\right)^2}\)
Giải hệ pt
1/\(\left\{{}\begin{matrix}4x\sqrt{y+1}+8x=\left(4x^2-4x-3\right)\sqrt{x+1}\\\dfrac{x}{x+1}+x^2=\left(y+2\right)\sqrt{\left(x+1\right)\left(y+1\right)}\end{matrix}\right.\)
2/\(\left\{{}\begin{matrix}x\sqrt{y^2+6}+y\sqrt{x^2+3}=7xy\\x\sqrt{x^2+3}+y\sqrt{y^2+6}=x^2+y^2+2\end{matrix}\right.\)\(\left\{{}\begin{matrix}x\sqrt{y^2+6}+y\sqrt{x^2+3}=7xy\\x\sqrt{x^2+3}+y\sqrt{y^2+6}=x^2+y^2+2\end{matrix}\right.\)
3/\(\left\{{}\begin{matrix}\left(2x+y-1\right)\left(\sqrt{x+3}+\sqrt{xy}+\sqrt{x}\right)=8\sqrt{x}\\\left(\sqrt{x+3}+\sqrt{xy}\right)^2+xy=2x\left(6-x\right)\end{matrix}\right.\)\(\left\{{}\begin{matrix}\left(2x+y-1\right)\left(\sqrt{x+3}+\sqrt{xy}+\sqrt{x}\right)=8\sqrt{x}\\\left(\sqrt{x+3}+\sqrt{xy}\right)^2+xy=2x\left(6-x\right)\end{matrix}\right.\)
4/\(\left\{{}\begin{matrix}\sqrt{xy+x+2}+\sqrt{x^2+x}-4\sqrt{x}=0\\xy+x^2+2=x\left(\sqrt{xy+2}+3\right)\end{matrix}\right.\)\(\left\{{}\begin{matrix}\sqrt{xy+x+2}+\sqrt{x^2+x}-4\sqrt{x}=0\\xy+x^2+2=x\left(\sqrt{xy+2}+3\right)\end{matrix}\right.\)
m.n giúp e mấy bài này vs ạ!!
giải bất phương trình \(\left(\sqrt{13}-\sqrt{2x^2-2x+5}-\sqrt{2x^2-4x+4}\right)\left(x^6-x^3+x^2-x+1\right)\ge0\)
Giải phương trình vô tỉ:
a) \(4x^2-4x-10=\sqrt{8x^2-6x-10}\)
b) \(\sqrt{\left(x+1\right)\left(2-x\right)}=1+2x-2x^2\)
c) \(\sqrt{3x+8+6\sqrt{3x-1}}+\sqrt{3x+8-6\sqrt{3x-1}}=3x+4\)
d) \(2x\sqrt{x^2-x+1}+4\sqrt{3x+1}=2x^2+2x+6\)
