\(\dfrac{x+1}{2}=2^5:2^3\)
\(\Leftrightarrow\dfrac{x+1}{2}=2^{5-3}\)
\(\Leftrightarrow\dfrac{x+1}{2}=2^2\)
\(\Leftrightarrow\dfrac{x+1}{2}=4\)
\(\Leftrightarrow\dfrac{x}{2}+\dfrac{1}{2}=4\)
\(\Leftrightarrow\dfrac{x}{2}=4-\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{x}{2}=\dfrac{8}{2}-\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{x}{2}=\dfrac{8-1}{2}\)
\(\Leftrightarrow\dfrac{x}{2}=\dfrac{7}{2}\)
\(\Leftrightarrow x=\dfrac{7}{2}.2\)
\(\Leftrightarrow x=7\)
Vậy \(x=7\)
x+\(\dfrac{1}{2}=2^5:2^3\)
=>x+\(\dfrac{1}{2}=2^2=4\)
=>x=\(\dfrac{7}{2}\)