\(=x-\sqrt{x}+\dfrac{1}{4}-\dfrac{37}{4}\)
\(=\left(\sqrt{x}-\dfrac{1}{2}\right)^2-\dfrac{37}{4}\)
\(=\left(\sqrt{x}-\dfrac{1}{2}-\dfrac{\sqrt{37}}{2}\right)\left(\sqrt{x}-\dfrac{1}{2}+\dfrac{\sqrt{37}}{2}\right)\)
\(A=\dfrac{\sqrt{x}+2}{\sqrt{x}-2}-\dfrac{3}{\sqrt{x}+2}+\dfrac{12}{x-4}\)
\(B=\dfrac{\sqrt{x}}{\sqrt{x}-3}-\dfrac{\sqrt{x}-21}{9-x}\dfrac{1}{\sqrt{x}+3}\)
\(C=\dfrac{\sqrt{x}}{\sqrt{x}+3}+\dfrac{2\sqrt{x}}{\sqrt{x}-3}-\dfrac{3x+9}{x-9}\)
\(D=\dfrac{1}{\sqrt{x}+3}-\dfrac{\sqrt{x}}{3-\sqrt{x}}+\dfrac{2\sqrt{x}+12}{x-9}\)
\(N=\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}-\dfrac{6}{x-1}\)
\(M=\dfrac{3}{\sqrt{x}-3}+\dfrac{2}{\sqrt{x}+3}+\dfrac{x-5\sqrt{x}-3}{x-9}\)
\(B=\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{x+9\sqrt{x}}{9-x};\left(x\ge0;x\ne9;x\ne16\right)\)
\(B=\dfrac{3}{\sqrt{x}-3}+\dfrac{2}{\sqrt{x}+3}+\dfrac{x-5\sqrt{x}-3}{x-9}\)
\(B=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}-\dfrac{x+\sqrt{x}}{x-1};\left(x>0;x\ne1\right)\)
tính rồi rút gọn
A=\((\frac{\sqrt{x}}{\sqrt{x}+1}+\frac{1}{\sqrt{x}})\times\frac{x+\sqrt{x}}{\sqrt{x}}\)
B=\(\frac{\sqrt{x}}{\sqrt{x}+3}+\frac{2\sqrt{x}}{\sqrt{x}-3}-\frac{3x+9}{x-9}\)
C=\((\frac{x+\sqrt{x}+10}{x-9}-\frac{1}{\sqrt{x}-3}):\frac{1}{\sqrt{x}-3}\)
\(\dfrac{x+\sqrt{x}-6}{x-9}+\dfrac{x-7\sqrt{x}+19}{x+\sqrt{x}-12}-\dfrac{x-5\sqrt{x}}{x+4\sqrt{x}}\)với x>0 x≠9
A= \(\left[\left(\dfrac{2\sqrt{x}}{\sqrt{x}+3}\right)+\dfrac{\sqrt{x}}{\sqrt{x}+3}+3\left(\dfrac{\sqrt{x}}{x-9}\right)\right]:\left(\dfrac{2\sqrt{x}-2}{\sqrt{x}-3}-\dfrac{1}{1}\right)\)với x>= 0 , x #9
b) 1/(sqrt(x) + 3) - (sqrt(x) - 3)/(x - 9) (với x > 0; x =9)
A=(\(\dfrac{\sqrt{x}}{\sqrt{x}+3}-\dfrac{x+9}{x-9}\)):(\(\dfrac{3\sqrt{x+1}}{x-3\sqrt{x}}-\dfrac{1}{\sqrt{x}}\)) (với x>0,x khác 9)
a,rút gọn biểu thức A
b,tìm x sao cho A>-1
Cho biểu thức: \(P=\left(1-\dfrac{x-3\sqrt{x}}{x-9}\right):\left(\dfrac{9-x}{x+\sqrt{x}-6}-\dfrac{\sqrt{x}-3}{2-\sqrt{x}}-\dfrac{2-\sqrt{x}}{\sqrt{x}+3}\right)\)
a) rút gọn P
b) tìm x để P>0
Rút gọn biểu thức:
\(\dfrac{2\sqrt{x}-9}{x-5\sqrt{x}+6}-\dfrac{\sqrt{x}+3}{\sqrt{x}-2}-\dfrac{2\sqrt{x}+1}{3-\sqrt{x}}\)
Rút gọn biểu thức
A=\(\dfrac{2\sqrt{x}-9}{x-5\sqrt{x}+6}\)- \(\dfrac{\sqrt{x}+1}{\sqrt{x}-2}\)+\(\dfrac{2\sqrt{x}+1}{3-\sqrt{x}}\)
