\(x-\sqrt{2x-5}=4\)
ĐK: \(\left\{{}\begin{matrix}2x-5\ge0\\x\ge4\end{matrix}\right.\)\(\Leftrightarrow x\ge4\)
\(x-\sqrt{2x-5}=4\Leftrightarrow\sqrt{2x-5}=x-4\)
Ta bình phương 2 vế:
\(2x-5=\left(x-4\right)^2\)
\(\Leftrightarrow2x-5=x^2-8x+16\)
\(\Leftrightarrow x^2-10x+21=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=7\left(nhận\right)\\x=3\left(loại\right)\end{matrix}\right.\)
refer
https://hoc247.net/hoi-dap/toan-9/giai-phuong-trinh-x-can-2x-5-4-faq446795.html