Help me... Giup đk chừng nào hay chừng đó ạ.
Bài 1:a, dfrac{x}{x-1}-dfrac{2x}{x^2-1}0
b, dfrac{left(x+2right)^2}{2x-3}-1dfrac{x^2+10}{2x-3}
c,dfrac{x+5}{x-5}-dfrac{x-5}{x+5}dfrac{20}{x^2-25}
d,dfrac{3x+2}{3x-2}-dfrac{6}{2+3x}dfrac{9x^2}{9x^2-4}
e,dfrac{3}{5x-1}+dfrac{2}{3-5x}dfrac{4}{left(1-5xright)left(5x-3right)}
f,dfrac{3}{1-4x}dfrac{2}{4x+1}-dfrac{8+6x}{16x^2-1}
g,dfrac{y-1}{y-2}-dfrac{5}{y+2}dfrac{12}{y^2-4}+1
h,dfrac{x+1}{x-1}-dfrac{x-1}{x+1}dfrac{4}{x^2-1}
i,dfrac{2x-3}{x+2}-dfra...
Đọc tiếp
Help me... Giup đk chừng nào hay chừng đó ạ.
Bài 1:a, \(\dfrac{x}{x-1}-\dfrac{2x}{x^2-1}=0\)
b, \(\dfrac{\left(x+2\right)^2}{2x-3}-1=\dfrac{x^2+10}{2x-3}\)
c,\(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\)
d,\(\dfrac{3x+2}{3x-2}-\dfrac{6}{2+3x}=\dfrac{9x^2}{9x^2-4}\)
e,\(\dfrac{3}{5x-1}+\dfrac{2}{3-5x}=\dfrac{4}{\left(1-5x\right)\left(5x-3\right)}\)
f,\(\dfrac{3}{1-4x}=\dfrac{2}{4x+1}-\dfrac{8+6x}{16x^2-1}\)
g,\(\dfrac{y-1}{y-2}-\dfrac{5}{y+2}=\dfrac{12}{y^2-4}+1\)
h,\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4}{x^2-1}\)
i,\(\dfrac{2x-3}{x+2}-\dfrac{x+2}{x-2}=\dfrac{2}{x^2-4}\)
j,\(\dfrac{x-1}{x^2-4}=\dfrac{3}{2-x}\)
