\(x-\dfrac{1}{2}\left(1-x\right)\) > 0
\(\Leftrightarrow x-\dfrac{1}{2}+\dfrac{x}{2}>0\)
\(\Leftrightarrow\dfrac{2.x}{2}-\dfrac{1}{2}+x>0\)
\(\Leftrightarrow2x-1+x>0\)
\(\Leftrightarrow\) \(3x>1\)
\(\Leftrightarrow x>\dfrac{1}{3}\)
Vậy để \(x-\dfrac{1}{2}\left(1-x\right)>0\) thì \(x>\dfrac{1}{3}\)
h) \(\dfrac{x}{2}-\dfrac{1}{x}=\dfrac{1}{12}\)
i) \(x^2-\dfrac{7}{6}x+\dfrac{1}{3}=0\)
k) \(\dfrac{13}{x-1}+\dfrac{5}{2x-2}-\dfrac{6}{3x-3}\)
g) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}=\dfrac{2}{9-6x}-\dfrac{3}{2}\)
h) \(\dfrac{x}{2}-\dfrac{1}{x}=\dfrac{1}{12}\)
i) \(x^2-\dfrac{7}{6}x+\dfrac{1}{3}=0\)
k) \(\dfrac{13}{x-1}+\dfrac{5}{2x-2}-\dfrac{6}{3x-3}\)
m) \(\left(\dfrac{3}{2}-\dfrac{2}{-5}\right):x-\dfrac{1}{2}=\dfrac{3}{2}\)
n) \(\left(\dfrac{3}{2}-\dfrac{5}{11}-\dfrac{3}{13}\right)\left(2x-2\right)=\left(-\dfrac{3}{4}+\dfrac{5}{22}+\dfrac{3}{26}\right)\)
Tìm x, biết
a/ (x + 1 ) (x - 2 ) <0
b/ (x - 3 ) (x - 4 ) > 0
c/\(\dfrac{1}{2}\)-(\(\dfrac{1}{3}\)+\(\dfrac{1}{4}\))<x<\(\dfrac{1}{48}\)-(\(\dfrac{1}{16}\)-\(\dfrac{1}{6}\))
a)2x.(x-\(\dfrac{1}{7}\) ) =0
b) \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
c) \(4\dfrac{5}{9}:2\dfrac{5}{18}-7< x< \left(3\dfrac{1}{5}:3,2+4,5.1\dfrac{31}{45}\right)\)
a\(\left(4x-5\right)\left(3x+2\right)=0\)
b\(\dfrac{x+1}{2016}+\dfrac{x+2}{2015}=\dfrac{x+3}{2014}+\dfrac{x+4}{2013}\)
Tìm x biết
a,\(x.\sqrt{x-2}=0\)
b, \(\sqrt{x}.\left(x^2-4\right)=0\)
c,\(\dfrac{|x|}{x}=1\)
1, Cho biểu thức P=\(\dfrac{1000}{100-x}\)với x thuộc Z và x khác 0. Tìm giá trị của x để P có giá trị lớn nhất. T2im giá trị lớn nhất đó của P.
2, Cho các biểu thức:
A=\(\left(\dfrac{1}{8.14}+\dfrac{1}{14.20}+\dfrac{1}{20.26}+...+\dfrac{1}{50.56}\right)\)
B=\(\left(\dfrac{45}{12.21}+\dfrac{45}{21.30}-\dfrac{40}{24.34}-\dfrac{40}{34.44}-\dfrac{40}{44.54}-\dfrac{40}{54.64}\right)\)
Chứng minh rằng \(\dfrac{A}{B}< \dfrac{1}{8}\)
tim x
\(\dfrac{5}{6}x-\dfrac{3}{4}=\dfrac{-1}{4}+\dfrac{2}{3}\)
\(-1\dfrac{1}{2}-\dfrac{2}{3}x=\dfrac{5}{6}-\left(\dfrac{-2}{5}\right)\)
\(\left(\dfrac{4}{5}:x+1,5\right):\dfrac{2}{3}=-1,5\)
\(\dfrac{4}{3}x-\dfrac{2}{3}=\dfrac{1}{4}-x\)
giup minh nhe minh dang can gap
Tìm x biết :\(\dfrac{1}{x\left(x+1\right)}\) +\(\dfrac{1}{\left(x+1\right)\left(x+2\right)}\) \(\dfrac{1}{\left(x+2\right)\left(x+3\right)}\) -\(\dfrac{1}{x}\) =\(\dfrac{1}{2010}\)
