Question

|x-3,5|+|y-1,3|=0

Answer 1

\(\left|x-3,5\right|+\left|y-1,3\right|=0\)

Ta có:

\(\left\{{}\begin{matrix}\left|x-3,5\right|\ge0\\\left|y-1,3\right|\ge0\end{matrix}\right.\forall xy.\)

\(\Rightarrow\left|x-3,5\right|+\left|y-1,3\right|=0\)

\(\Rightarrow\left\{{}\begin{matrix}x-3,5=0\\y-1,3=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0+3,5\\y=0+1,3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=3,5\\y=1,3\end{matrix}\right.\)

Vậy \(\left(x;y\right)\in\left\{3,5;1,3\right\}.\)

Chúc bạn học tốt!

Answer 2

Các bạn giúp mk nhanh vs nhá, chiều mai mk cần. cảm ơn trước