Ta có: \(\left(x-2\right)^3+\left(3x-1\right)\left(3x+1\right)=\left(x+1\right)^3\)
\(\Leftrightarrow x^3-6x^2+12x-8+9x^2-1=x^3+3x^2+3x+1\)
\(\Leftrightarrow x^3+3x^2+12x-9-x^3-3x^2-3x-1=0\)
\(\Leftrightarrow9x-10=0\)
\(\Leftrightarrow9x=10\)
hay \(x=\frac{10}{9}\)
Vậy: \(x=\frac{10}{9}\)
(x-2)3+(3x-1)(3x+1)=(x+1)3
bài 2 giải các phương trình sau
b,2(x+3)-4=0
d,5(x-3)=3x-5
f,7(5-x)=11-5x
h,2(3x-1)-3x=10
j,3-2x=3.(x+1)-x-2
m,4(2x-3)-5=6(3-x)-7
(x-2)3+(3x-1)(3x+1)=(x+1)3
a.(x+5)(2x-1)=(2x-3)(x+1)
b.(x+1)(x+9)=(x+3)(x+5)
c.(3x+5)(2x+1)=(6x-2)(x-3)
d.(x-2)(3x+5)=(2x-4)(x+1)
đ.9x2 -1=(3x+1)(2x-3)
e.(2x+5)(x-4)=(x-5)(4-x)
a)5-(x-6)=4(3-2x)
b)2x(x+2)2-8x2=2(x-2)(x2+2x+4)
c)7-(2x+4)=-(x+4)
d)(x-2)3+(3x-1)(3x+1)=(x+1)3
e)(x+1)(2x-3)=(2x-1)(x+5)
f)(x-1)3-x(x+1)2=5x(2-x)-11(x+2)
g)(x-1)-(2x-1)=9-x
h)(x-3)(x+4)-2(3x-2)=(x+4)2
i)x(x+3)2-3x=(x+2)33+11
j)(x+1)(x2-x+1)-2x=x(x+1)(x-1)
Câu 1: Giải các phương trình sau:
a) 3x-2(x-3)=0
b) (x+1) (2x-3) = ( 2x -1) (x +5)
c) 2x/ x-1 -x/x+1 =1
d) (2x +3) (3x-5)=0
e) x-2/x+2-3/x-2 = 2(x-11)/ x2
giúp mình với ạ huhu\(^{ }\)
Giải phương trình
1) 2x+1=15-5x
2) 3x-2=2x+5
3) 7 (x-2)=5 (3x+1)
4) 2x+5=20-3x
5) -4x +8=0
6) x-3=10-5x
7) 3x-1=x+3
8) 2(x+1)=5x-7
Giair phương trình sau :
\(\left(x-2\right)^3+\left(3x-1\right)\left(3x+1\right)=\left(x+1\right)^3\)
1. giải phương trình
a, \(\frac{3x-2}{x-3}+1=\frac{5}{x-3}\)
b,\(\frac{3x-2}{x-3}-1=\frac{2x+1}{x-3}\)
