Question

(X-1)^x+2=(x-1)^x+4 

giải thích rõ giúp em vs ạ

 

Answer 1

Sai thì thoi nha

\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\)

\(\Leftrightarrow\cdot\dfrac{\left(x-1\right)^{x+2}}{\left(x-1\right)^{x+4}}=1\)

\(\Leftrightarrow\cdot\dfrac{\left(x-1\right)^x.\left(x-1\right)^2}{\left(x-1\right)^x.\left(x-1\right)^4}=1\)

\(\Leftrightarrow\cdot\dfrac{1}{\left(x-1\right)^2}=1\)

\(\Leftrightarrow\left(x-1\right)^2=1\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=1\\x-1=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)