| x- 1/3 | = 5/6
Ta có:
TH1: x-1/3=5/6
x= 5/6+1/3
x= 7/6
TH2: x-1/3=-5/6
x= -5/6+1/3
x= -1/2
Vậy x=7/6, -1/2
\(\left|x-\dfrac{1}{3}\right|=\dfrac{5}{6}\)
Có \(\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{5}{6}\\x-\dfrac{1}{3}=\dfrac{-5}{6}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{6}\\x=\dfrac{-1}{2}\end{matrix}\right.\)
\(\Rightarrow x=\left\{\dfrac{7}{6};\dfrac{-1}{2}\right\}\)