a, x+2/3=5/6.3/10 x+2/3=1/4 x =1/4-2/3 x =-5/12
b, 7/8-5/9:x=1/6
5/9:x=7/8-1/6
5/9:x=17/24
x=5/9:17/24
x=40/51
c,|x|+1/5=3/2
|x| =3/2-1/5
|x| =13/10
Suy Ra x=13/10 hoặc x=-13/10
a)
\(x+\dfrac{2}{3}=\dfrac{5}{6}\cdot\dfrac{3}{10}\\ x+\dfrac{2}{3}=\dfrac{1}{4}\\ x=\dfrac{1}{4}-\dfrac{2}{3}=\dfrac{-5}{12}\)
b)
\(\dfrac{7}{9}-\dfrac{5}{9}:x=\dfrac{1}{6}\\ \dfrac{5}{9}:x=\dfrac{7}{9}-\dfrac{1}{6}=\dfrac{11}{18}\\ x=\dfrac{5}{9}:\dfrac{11}{18}=\dfrac{10}{11}\)
c)
\(\left|x\right|+\dfrac{1}{5}=\dfrac{3}{2}\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{2}\\x+\dfrac{1}{5}=-\dfrac{3}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}-\dfrac{1}{5}=\dfrac{13}{10}\\x=-\dfrac{3}{2}-\dfrac{1}{5}=-\dfrac{17}{10}\end{matrix}\right.\)
Vậy có 2 giá trị của \(x\) là: \(\dfrac{13}{10}\) và \(-\dfrac{17}{10}\)
a)\(x+\dfrac{2}{3}=\dfrac{5}{6}.\dfrac{3}{10}\)
\(x+\dfrac{2}{3}=\dfrac{1}{4}\)
\(x=\dfrac{1}{4}-\dfrac{2}{3}\)
\(x=\dfrac{-5}{12}\)
Vậy \(x=\dfrac{-5}{12}\)
b)\(\dfrac{7}{9}-\dfrac{5}{9}:x=\dfrac{1}{6}\)
\(\dfrac{5}{9}:x=\dfrac{7}{9}-\dfrac{1}{6}\)
\(\dfrac{5}{9}:x=\dfrac{11}{18}\)
\(x=\dfrac{5}{9}:\dfrac{11}{18}\)
\(x=\dfrac{10}{11}\)
Vậy \(x=\dfrac{10}{11}\)
c)\(\left|x\right|+\dfrac{1}{5}=\dfrac{3}{2}\)
\(\left|x\right|=\dfrac{3}{2}-\dfrac{1}{5}\)
\(\left|x\right|=\dfrac{13}{10}\)
TH1:\(x=\dfrac{13}{10}\) TH2:\(x=\dfrac{-13}{10}\)
Vậy \(x\) thuộc \(\dfrac{13}{10},\dfrac{-13}{10}\)
mk sửa lại câu c
c) \(\left|x\right|+\dfrac{1}{5}=\dfrac{3}{2}\\ \left|x\right|=\dfrac{3}{2}-\dfrac{1}{5}=\dfrac{13}{10}\)
vậy có 2 giá trị của \(x\) là \(\dfrac{13}{10}\) và \(-\dfrac{13}{10}\)
