\(x:\left(3\dfrac{1}{2}-5\dfrac{1}{6}\right)=4\dfrac{1}{5}-6\dfrac{2}{3}\)
<=>\(x:\dfrac{2}{3}=\dfrac{-37}{15}\)
<=>\(\dfrac{-37}{15}\cdot\dfrac{2}{3}\)
<=>\(\dfrac{-74}{45}\)
Bài 2:Tìm x biết:
a)\(\dfrac{1}{7}+x=\dfrac{-2}{3}\)
b)\(\dfrac{-2}{3}:x=\dfrac{-5}{6}\)
c)\(\left\{\dfrac{3}{5}-2x\right\}.\dfrac{5}{8}=1\)
d)\(\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}\)
e)\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
f)\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
g)\(\left|X+\dfrac{1}{3}\right|-4=\dfrac{-1}{2}\)
h)\(\left(\dfrac{1}{32}\right)^x.8^{2x}=512\)
i)\(5,3x+\left(-3,3\right)x+1,7=-4,9\)
tìm x
\(\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}\)
\(2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}\)
\(\left(\dfrac{5}{6}x-0,3\right):2\dfrac{1}{3}=25\%\)
\(\dfrac{4}{7}-\dfrac{2}{3}x=1,5+\dfrac{4}{5}x\)
GIÚP MÌNH NHÉ
a,\(\dfrac{-4}{5}-\left(\dfrac{2}{3}x+1\dfrac{1}{4}\right)=\dfrac{2}{7}\)
b\(\dfrac{5}{6}+\left(\dfrac{3}{4}-\dfrac{1}{2}:x\right)=\dfrac{-2}{3}\)
c\(\left(\dfrac{4}{5}x-1\dfrac{1}{3}\right):\dfrac{3}{4}=0,7\)
d\(\dfrac{5}{6}-\dfrac{3}{4}x=1\dfrac{1}{3}+0,5x\)
giúp mình nhé mình đang cần gấp
tìm x
a\(\dfrac{2}{3}x-\dfrac{5}{6}=-1\dfrac{1}{2}x+0,75\)
b\(\left(5x-3\right).\left(2x+5\right)=0\)
c\(\left(\dfrac{5}{6}:x-1\dfrac{1}{4}\right)^4=\dfrac{81}{16}\)
d\(\left|\dfrac{2}{5}x-0,2\right|.1\dfrac{1}{4}-2=1,5\)
giúp mình nhé
tìm x
a,\(\dfrac{5}{6}-\left(\dfrac{3}{6}x-\dfrac{1}{5}\right)=\dfrac{-5}{12}\)
b\(\left(4x-3\right).\left(\dfrac{5}{4}x+2\right)=0\)
c\(\left|\dfrac{7}{8}x-\dfrac{2}{3}\right|-\dfrac{3}{4}=1,5\)
d\(\left(\dfrac{3}{5}x-\dfrac{1}{2}\right)^3=\dfrac{8}{125}\)
giúp mình nhé mình đang cần gấp
Tìm \(x,y\in Z\) biết
a) \(\dfrac{3}{x}+\dfrac{y}{3}=\dfrac{5}{6}\)
b)\(\dfrac{5}{x}-\dfrac{y}{3}=\dfrac{1}{6}\)
c)\(\dfrac{x}{6}-\dfrac{2}{y}=\dfrac{1}{30}\)
d)\(xy+2x-y=15\)
Tìm x biết: (x-\(\dfrac{2}{3}\))\(^2\)=\(\dfrac{5}{6}\)
tìm x
a,\(\dfrac{6}{7}-\dfrac{3}{4}x=-1\dfrac{1}{2}x-3\)
b\(\left(4x-1\right)^2=\left(4x-1\right)^4\)
c\(\left(\dfrac{4}{5}-\dfrac{3}{4}:x\right)^3=\dfrac{-1}{27}\)
d\(\left|\dfrac{4}{3}-\dfrac{1}{4}x\right|:2\dfrac{1}{3}=0,5\)
giúp mình nhé
Tìm x, biết: A=\(\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{20}+...+\dfrac{2}{x.\left(x+1\right)}=\dfrac{4}{5}\)
