\(\frac{2x\left(x+1\right)}{3x+4}=0\left(x\ne-\frac{4}{3}\right)\)\(\Leftrightarrow2x\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\left(TM\right)\)
\(\frac{3x\left(x-5\right)}{x-7}=0\left(x\ne7\right)\)\(\Leftrightarrow3x\left(x-5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\left(TM\right)\)
KL: ...............................
2x(x+1)3x+4=0(x≠−43)2x(x+1)3x+4=0(x≠−43)⇔2x(x+1)=0⇔[x=0x+1=0⇔[x=0x=−1(TM)⇔2x(x+1)=0⇔[x=0x+1=0⇔[x=0x=−1(TM)
3x(x−5)x−7=0(x≠7)3x(x−5)x−7=0(x≠7)⇔3x(x−5)=0⇔[x=0x−5=0⇔[x=0x=5(TM)
