Question

viet cac bieu thuc sau duoi dang tich:

a, 27x\(^3\)-27x\(^2\)+3x+1

b,x\(^3\)-3x\(^2\)+3x-1

c,\(\dfrac{1}{27}\)+x\(^3\)

d, 0,001-1000x\(^3\)

Answer 1

a: Sửa đề: \(27x^3-27x^2+9x-1\)

\(=\left(3x-1\right)^3\)

b: \(=\left(x-1\right)^3\)

c: \(=\left(x+\dfrac{1}{3}\right)\left(x^2-\dfrac{1}{3}x+\dfrac{1}{9}\right)\)