Question

viet cac bieu thuc sau duoi dang tich:

a, 27x\(^3\)-27x\(^2\)+3x+1

b,x\(^3\)-3x\(^2\)+3x-1

c,\(\dfrac{1}{27}\)+x\(^3\)

d, 0,001-1000x\(^3\)

Answer 1

Câu a : ( Mình nghĩ đề sai )

Câu b : \(x^3-3x^2+3x-1=\left(x-1\right)^3=\left(x-1\right)\left(x-1\right)\left(x-1\right)\)

Câu c : \(\dfrac{1}{27}+x^3=\left(\dfrac{1}{3}\right)^3+x^3=\left(\dfrac{1}{3}+x\right)\left(\dfrac{1}{9}-\dfrac{1}{3}x+x^2\right)\)

Câu d : \(0,001-1000x^3=\left(\dfrac{1}{10}\right)^3-\left(10x\right)^3=\left(\dfrac{1}{10}-10x\right)\left(\dfrac{1}{100}+x+100x^2\right)\)

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