Thái Thùy Linh
nNaOH= 2*0.1=0.2 mol
PTHH: NaOH + HCl = NaCl + H2O
0.2............0.2
a) VHCl = 0.2/2= 0.1 mol
b) PTHH: 2NaOH + H2SO4 = Na2SO4 + 2H2O
0.2.............0.1
mH2SO4= 0.1*98=9.8g
=>mddH2SO4 = \(\dfrac{m_{ct}\cdot100}{C\%}\) =\(\dfrac{9.8\cdot100}{24.5}=\) 40g