Question

Tính
\(\frac{4x^2-16}{1-2x+x^2}:\frac{3x+6}{1-x}\)

Answer 1

\( {4x^2-16{} \over 1-2x+x^2}\):\( {3x +6{} \over 1-x}\)

=

Answer 2

xin loi nhé

=\( {(2x-4) (2x+4){} \over (1-x)^2}\):\( {3. {(x+2)} \over 1-x}\)

=\( {4{(x-2)(x+2)} \over (1-x)^2}\).\({1-x \over 3(x+2)}\)

=\({4{(x-2)} \over 3(1-x)}\)