Question

Tính:

\(x=\sqrt{6-2\sqrt{\sqrt{2}+2\sqrt{3}+\sqrt{18}-8\sqrt{2}}}\)

Answer 1

\(x=\sqrt{6-2\sqrt{\sqrt{2}+2\sqrt{3}+\sqrt{18-8\sqrt{2}}}}=\sqrt{6-2\sqrt{\sqrt{2}+2\sqrt{3}+\left(4-\sqrt{2}\right)}}=\sqrt{6-2\sqrt{4+2\sqrt{3}}}=\sqrt{6-2\left(\sqrt{3}+1\right)}=\sqrt{4-2\sqrt{3}}=\sqrt{3}-1\)

Answer 2

Gửi bạn

Answer 3

Sửa lại đề nhé!!!!!!!

\(x=\sqrt{6-2\sqrt{\sqrt{2}+2\sqrt{3}+\sqrt{18-8\sqrt{2}}}}\)