Question

Tính nhanh:

\(\left(\dfrac{-3}{7}+\dfrac{4}{11}\right):\dfrac{7}{11}+\left(\dfrac{-4}{7}+\dfrac{7}{11}\right):\dfrac{7}{11}\)

Các bn giúp mk vs nha

Answer 1

Giải:

\(\left(\dfrac{-3}{7}+\dfrac{4}{11}\right):\dfrac{7}{11}+\left(-\dfrac{4}{7}+\dfrac{7}{11}\right):\dfrac{7}{11}\)

\(=\left(\dfrac{-3}{7}+\dfrac{4}{11}\right).\dfrac{11}{7}+\left(-\dfrac{4}{7}+\dfrac{7}{11}\right).\dfrac{11}{7}\)

\(=\left[\dfrac{-3}{7}+\dfrac{4}{11}+\left(-\dfrac{4}{7}\right)+\dfrac{7}{11}\right].\dfrac{11}{7}\)

\(=\left[\dfrac{-3}{7}+\left(-\dfrac{4}{7}\right)+\dfrac{4}{11}+\dfrac{7}{11}\right].\dfrac{11}{7}\)

\(=\left[\dfrac{-7}{7}+\dfrac{11}{11}\right].\dfrac{11}{7}\)

\(=\left[-1+1\right].\dfrac{11}{7}\)

\(=0.\dfrac{11}{7}=0\)

Vậy ...

Answer 2

\(\left(\dfrac{-3}{7}+\dfrac{4}{11}\right):\dfrac{7}{11}+\left(\dfrac{-4}{7}+\dfrac{7}{11}\right):\dfrac{7}{11}\)

= \(\left(\dfrac{-3}{7}+\dfrac{4}{11}\right).\dfrac{11}{7}+\left(\dfrac{-4}{7}+\dfrac{7}{11}\right).\dfrac{11}{7}\)

= \(\left(\dfrac{-3}{7}+\dfrac{4}{11}+\dfrac{-4}{7}+\dfrac{7}{11}\right)\)\(.\dfrac{11}{7}\)

= \(\left(-1+1\right).\dfrac{11}{7}\)

= \(0.\dfrac{11}{7}\)

= \(0\)