\(C_2H_5OH+CH_3COOH\rightarrow CH_3COOC_2H_5\)
\(m_{CH_3COOC_2H_5\left(lt\right)}=\frac{14,8.100}{80}=18,5\left(g\right)\)
\(\rightarrow n_{CH_3COOC_2H_5\left(lt\right)}=\frac{18,5}{88}=\frac{37}{176}\left(mol\right)\)
\(\)theo phương trình:\(n_{C_2H_5OH}=n_{CH_3COOC_2H_5}=\frac{37}{176}\left(mol\right)\)
\(\Rightarrow m_{C_2H_5OH}=\frac{37}{176}.46\approx9,67\left(g\right)\)