Question

Tính khối lượng a) 0,2 mol O2 b) 22,4l khí CO2

Answer 1

\(m_{O_2}=0.2\cdot32=6.4\left(g\right)\)

\(n_{CO_2}=\dfrac{22.4}{22.4}=1\left(mol\right)\)

\(m_{CO_2}=1\cdot44=44\left(g\right)\)

Answer 2

\(a) m_{O_2} = 0,2.32 = 6,4(gam)\\ b) n_{CO_2} = \dfrac{22,4}{22,4} = 1(mol)\\ m_{CO_2} = 1.44 = 44(gam)\)