a: \(=\dfrac{58}{3}\cdot\dfrac{3}{7}-\dfrac{100}{3}=\dfrac{58}{7}-\dfrac{100}{3}=\dfrac{-526}{21}\)
b: \(=9\cdot\dfrac{1}{4}+\dfrac{1}{3}=\dfrac{9}{4}+\dfrac{1}{3}=\dfrac{27+4}{12}=\dfrac{31}{12}\)
c: \(=\dfrac{-7}{5}\left(15+\dfrac{1}{4}-25-\dfrac{1}{4}\right)=\dfrac{-7}{5}\cdot\left(-10\right)=14\)