thực hiện phép tính (tính hợp lí nếu có thể)
1) \(-0,75.\dfrac{12}{-5}.4\dfrac{1}{6}.\left(-1\right)^2\)
2) \(\dfrac{11}{25}.\left(-24,8\right)-\dfrac{11}{25}.75,2\)
3) \(\left(-\dfrac{3}{4}+\dfrac{2}{7}\right):\dfrac{2}{3}+\left(-\dfrac{1}{4}+\dfrac{5}{7}\right):\dfrac{2}{3}\)
4) \(\left(\dfrac{1}{2}-\dfrac{2}{3}\right)-\left(\dfrac{5}{3}-\dfrac{3}{2}\right)+\left(\dfrac{7}{3}-\dfrac{5}{2}\right)\)
5) \(\left(-2\right)^2+\sqrt{36}-\sqrt{9}+\sqrt{25}\)
6) \(\left(-\dfrac{1}{3}\right)^2.\dfrac{4}{11}+\dfrac{7}{11}.\left(-\dfrac{1}{3}\right)^2\)
5) \(\left(-2\right)^2+\sqrt{36}-\sqrt{9}+\sqrt{25}\)
=\(4+6-3+5\)
=\(12\)
2) \(\dfrac{11}{25}.\left(-24,8\right)-\dfrac{11}{25}.75,2\)
=\(\dfrac{11}{25}.\left(-24,8-75,2\right)\)
=\(\dfrac{11}{25}.\left(-100\right)\)
=\(-44\)
\(6\)) \(\left(-\dfrac{1}{3}\right)^2\).\(\dfrac{4}{11}+\dfrac{7}{11}.\left(-\dfrac{1}{3}\right)^2\)
=\(\left(-\dfrac{1}{3}\right)^2.\left(\dfrac{4}{11}+\dfrac{7}{11}\right)\)
=\(\left(-\dfrac{1}{3}\right)^2.1\)
=\(\dfrac{1}{9}\)
1: \(=\dfrac{3}{4}\cdot\dfrac{12}{5}\cdot\dfrac{25}{6}=\dfrac{36}{20}\cdot\dfrac{25}{6}=\dfrac{9}{5}\cdot\dfrac{25}{6}=\dfrac{9}{6}\cdot5=5\cdot\dfrac{3}{2}=\dfrac{15}{2}\)
3: \(=\dfrac{3}{2}\left(-\dfrac{3}{4}+\dfrac{2}{7}-\dfrac{1}{4}+\dfrac{5}{7}\right)=0\)
4: \(=\dfrac{1}{2}-\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{3}{2}+\dfrac{7}{3}-\dfrac{5}{2}=\dfrac{4}{2}-\dfrac{5}{2}=-\dfrac{1}{2}\)
5: \(=4+6-3+5=10+2=12\)
