\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(A=3,1-2,5+2,5-3,1\)
\(A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)
\(A=0-0\)
\(A=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(B=5,3-2,8-4-5,3\)
\(B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=0-6,8\\ B=-6,8\)
Tính giá trị:
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\\ A=3,1-2,5+2,5-3,1\\ A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\\ A=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\\ B=5,3-2,8-4-5,3\\ B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=-6,8\)
\(C=-\left(251.3\right)+281+3.251-\left(1-281\right)\)
\(C=\left[-\left(251.3\right)+3.251\right]+\left[281-\left(1-281\right)\right]\\ C=0+560\\ C=560\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\\ D=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\\ D=\left(-\dfrac{3}{5}-\dfrac{2}{5}\right)+\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)\\ D=-1+0\\ D=-1\)
\(C=-\left(251.3\right)+281+3.251-\left(1-281\right)\\ C=\left[-\left(251.3\right)+3.251\right]+\left[281-\left(1-281\right)\right]\\ C=0+\left[281+280\right]\\ C=0+561\\ C=561\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\\ D=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\\ D=\left(-\dfrac{3}{5}-\dfrac{2}{5}\right)-\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\\ D=-1-0\\ D=-1\)
A = (3,1 – 2,5) – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 -3,1 = 0
B = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 -4 -5,3
= (5,3 – 5,3 ) – (2,8 + 4) = -6,8
C = - (251.3 + 281) + 3.251 – (1- 281) = -251.3 -281 + 251.3 -1 + 281
= -251.3 + 251.3 -281 + 281 -1 = -1
A = (3,1 – 2,5) – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 -3,1 = 0
B = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 -4 -5,3
= (5,3 – 5,3 ) – (2,8 + 4) = -6,8
C = - (251.3 + 281) + 3.251 – (1- 281) = -251.3 -281 + 251.3 -1 + 281
= -251.3 + 251.3 -281 + 281 -1 = -1
