a) A = \(\frac{{2\cos {{45}^o}}}{{\sqrt 2 }} + \sqrt 3 \tan {30^o} = \frac{{2.\frac{{\sqrt 2 }}{2}}}{{\sqrt 2 }} + \sqrt 3 .\frac{{\sqrt 3 }}{3} = 1 + 1 = 2\)
b) B = \(\frac{{2\sin {{60}^o}}}{{\sqrt 3 }} - \cot {45^o} = \frac{{2.\frac{{\sqrt 3 }}{2}}}{{\sqrt 3 }} - 1 = 1- 1 = 0\).
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