`a)lim[2n^2+5]/[-3n^2-3]`
`=lim[2+5/[n^2]]/[-3-3/[n^2]]`
`=2/[-3]=-2/3`
`b)lim(-5n^3-2n^2+5n-6)`
`=lim n^3(-5-2/n+5/[n^2]-6/[n^3])`
Vì `{:(lim n^3=+oo),(lim (-5-2/n+5/[n^2]-6/[n^3])=-5):}}=>lim n^3(-5-2/n+5/[n^2]-6/[n^3])=-oo`
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