Tính:
a) \(\left(2^{-1}+3^{-1}\right):\left(2^{-1}-3^{-1}\right)+\left(2^{-1}.2^0\right):2^3\)
\(=\left(\frac{1}{2}+\frac{1}{3}\right):\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{2}.1\right):8\)
\(=\frac{5}{6}:\frac{1}{6}+\frac{1}{2}:8\)
\(=5+\frac{1}{16}\)
\(=\frac{81}{16}.\)
Chúc bạn học tốt!
Thực hiện phép tính
a) \(\left[6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)
b) \(\frac{\left(\frac{2}{3}\right)^3.\left(-\frac{3}{4}\right)^2.\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)
C=\(\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{99}}< -\frac{1}{2}\)
D=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{100^2}-1\right)< -\frac{1}{2}\)
A=\(\left[\frac{1}{100}-1^2\right].\left[\frac{1}{100}-\left(\frac{1}{2}\right)^2\right].\left[\frac{1}{100}-\left(\frac{1}{3}\right)^2\right]....\left[\frac{1}{100}-\left(\frac{1}{20}\right)^2\right]\)
Mọi người giúp em với ạ :'(
1/Tính
a)
\(\frac{2}{5}+\frac{1}{5}\times\left(\frac{3}{4}\right)\)
b)\(\frac{5}{12}\times\left(\frac{-3}{4}\right)+\frac{7}{12}\times\left(\frac{-3}{4}\right)\)
c)\(\frac{2^{15}\times9^4}{6^6\times8^3}\)
2/Tìm x biết:
a)\(\frac{5}{7}+\frac{2}{7}x=1\)
b)0,2+\(\left|x-1,3=1,5\right|\)
c)\(2^x+5=37\)
d)\(2^x+2^{x+1}=48\)
1)\(\frac{27^4.9^3}{81^2}\)
2)\(\left(\frac{1}{5^{^{ }}}\right)^{2002}.\left(-5\right)^{2000}\)
3)\(\frac{4^{11}.4^5}{2^{31}}\)
4)\(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}\)
5)\(4^2.\frac{25^2}{2^3.5^2}+32.125\)
\(\left(-2\right)^3+2^2+\left(-1\right)^{20}+\left(-2\right)^0\)
\(\left(2x+3\right)^2=\frac{9}{121}\\ \left(3x-1\right)^3=-\frac{8}{27}\)
\(\left(-\dfrac{1}{3}\right).\left(\dfrac{1}{3}\right)+\left(\dfrac{15}{2}\right)^7:\left(\dfrac{15}{2}\right)^5-\left(\left(-2\right)^2\right)^3\)
bài 1: thực hiện phép tính
a)\(\dfrac{2^5.8^4.4^3}{16^6}\)
b) \(\left(\dfrac{3}{5}-\dfrac{3}{4}\right).\left(\dfrac{2}{6}-\dfrac{1}{5}\right)^2\)
c)\(3.[\dfrac{-2}{5}]-\left(\dfrac{-1}{2}\right).4:\left(\dfrac{-1}{2}\right)^2\)
