A = \(\left(\sqrt{3}.\sqrt{4}-3.\sqrt{3}.\sqrt{25}\right).\sqrt{3}\)
= \(3\sqrt{4}-3.3.\sqrt{25}\)
= \(3.2-9.5\)
= -39
A = \(\left(\sqrt{3}.\sqrt{4}-3.\sqrt{3}.\sqrt{25}\right).\sqrt{3}\)
= \(3\sqrt{4}-3.3.\sqrt{25}\)
= \(3.2-9.5\)
= -39
Tính:
\(a.\) \(A=\sqrt{12}-2\sqrt{48}+\dfrac{7}{5}\sqrt{75}\)
\(b.\) \(B=\sqrt{14-6\sqrt{5}}+\sqrt{\left(2-\sqrt{5}\right)^2}\)
\(c.\) \(C=\left(\sqrt{6}-\sqrt{2}\right)\sqrt{2+\sqrt{3}}\)
\(d.\) \(D=\dfrac{5+\sqrt{5}}{\sqrt{5}+2}+\dfrac{\sqrt{5}-5}{\sqrt{5}}-\dfrac{11}{2\sqrt{5}+3}\)
Tính:
\(a)D=\left(\sqrt{2}-\sqrt{3-\sqrt{5}}\right)\left(-\sqrt{2}\right)\\ b)2\sqrt{3}\left(\sqrt{27}+2\sqrt{48}\right)-\sqrt{75}\\ c)E=\left(\sqrt{10}+\sqrt{6}\right)\sqrt{8-2\sqrt{15}}\\ d)P=\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}\)
\(e)M=-3\sqrt{50}+2\sqrt{98}-7\sqrt{72}\)
thực hiện phép tính
\(a,\sqrt{75}+\sqrt{\left(\sqrt{3}-2\right)^2}-30\sqrt{\frac{3}{25}}\)
\(b,\sqrt{11-4\sqrt{7}}-\frac{12}{1+\sqrt{7}}\)
Cho
\(\sqrt{a}+\sqrt{b}+\sqrt{c}=\sqrt{3}\)
\(\sqrt{\left(a+2b\right)\left(a+2c\right)}+\sqrt{\left(b+2a\right)\left(b+2c\right)}+\sqrt{\left(c+2a\right)\left(c+2b\right)}=3\)
Hãy tính \(\left(2\sqrt{a}+3\sqrt{b}-4\sqrt{c}\right)^2\)
Rút gọn
\(P=\frac{1}{3}\left(\sqrt[3]{2}+1\right)\left(\sqrt{12\sqrt[3]{2}-15}+2\sqrt{3\sqrt[3]{4}-3}\right)\)
\(P=\frac{1}{3}\left(\sqrt[3]{2}+1\right)\left(\sqrt{12\sqrt[3]{2}-15}+2\sqrt{3\sqrt[3]{4}-3}\right)\)
\(P=\frac{1}{3}\left(\sqrt[3]{2}+1\right)\left(\sqrt{12\sqrt[3]{2}-15}+2\sqrt{3\sqrt[3]{4}-3}\right)\)
thực hiện phép tính
\(\left(\dfrac{15}{\sqrt{6}+1}+\dfrac{4}{\sqrt{16}-2}-\dfrac{12}{3-\sqrt{16}}\right).\left(\sqrt{6}+11\right)\)
Tính giá trị của biểu thức \(P=x^3+y^3-3\left(x+y\right)+2009\)
trong đó: \(x=\sqrt[3]{3+2\sqrt{2}}+\sqrt[3]{3-2\sqrt{2}}\)
\(y=\sqrt[3]{17+12\sqrt{2}}+\sqrt[3]{17-12\sqrt{2}}\)
1. thực hiện phép tính
a, A=\(2\sqrt{3}-\sqrt{12}-\sqrt{9}\)
b,B=\(\sqrt{3}\left(\sqrt{12}+\sqrt{27}\right)\)
Thực hiện phép tính :
a, \(\left(\sqrt{15}+2\sqrt{3}\right)^2+12\sqrt{5}\)
b, \(\left(\sqrt{6}+2\right)\left(\sqrt{3}-\sqrt{2}\right)\)
c, \(\left(1+\sqrt{2}-\sqrt{3}\right)\left(1+\sqrt{2}+3\right)\)
d,